Calculate the number of atoms in 2.5 mol manganese. O 3.6 X 1024 Mn
O 0.44 X 1024 Mn
O 2.8 X 1023 Mn
O 1.5 X 1024 Mn
.

43.452

step-by-step explanation:

284 times .153 = 43.452

what are the statements

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol