How many grams of KClO3 are needed to make 30.0 g of KCI?

2KClO3 ==> 2 KCl + 3O2

393g O2 x 1 mole/32 g = 12.28 moles O2

moles KClO3 needed = 12.28 mol O2 x 2 mol KClO3/3mol O2 = 8.19 mol

grams KClO3 = 8.19 moles x 123g/mol = 1007g

Explanation:

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

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