Lab 8 Ouiz Name:
1. A student poured 1.2 mL of a volatile liquid into a 250 mL flask. The student then sealed the
flask (except for a very small hole) and lowered the flask into boiling water (100.0° C), allowin;
the liquid to vaporize and warm for 10 minutes. He then cooled the flask to condense the vapor
and he weighed it. Lastly, he washed the flask out, filled it with water and weighed it again.
Density of water is 1.00 g/mL
Barometric pressure = 751.3 mmHg
Mass of empty flask = 79.28 g
Flask with condensed vapor = 80.32 g
Flask with water = 347.84 g
a) Determine the pressure of the unknown vapor in atm.

explanation:

pv=nrt

explanation:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied