how many molecules of butane are contained in 25.0 ml of butane? the density of butane is 0.6011 g/ml and the molar mass is 58.12 g/mol.

 1.557 × 10²³ moleculesExplanation:

To determine the molecules of butane we can either use multiple steps or use a combined equation based on the following formulas:

Molecules of butane = Moles × Avogadro's Number

Moles of Butane = Mass ÷ Molar Mass

Mass of Butane = volume × Density

∴ Molecules of butane

   = [(volume × Density) ÷ Molar Mass]  × Avogadro's Number

   = ([(25.0 ml × 0.6011 g/ml) ÷ 58.12 g/mol] × (6.022 × 10²³ molecules/mol))

   = 1.557 × 10²³ molecules

∴ 25.0 ml of butane of density of 0.6011 g/ml contains 1.557 × 10²³ molecules.

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So what you would do is go through and add 3 teaspoons(tsp) 6 times because of the 6 tablespoons(tbsp). which will give you an answer of 18. another way is to multiply 3x6=18.