Calculate the Gibbs Free-Energy and the standard Gibbs Free- Energy by the cell in the given cell notation: Zn(s) |Zn2+(aq) || H+(aq)| H2(g) |Pt (s)
When [Zn+2] = 4.0 x 10 -3 M, [H2] = 0.010 M, [H+] = 1.0 M

i do not get it   at all

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o

lab safety rules

explanation: