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Chemistry, 07.10.2021 19:00 moonlightparis9015
Zinc sulfide reacts with oxygen according to the reaction:
2ZnS(s)+3O2(g)→2ZnO(s)+2SO2(g)
A reaction mixture initially contains 3.6 mol ZnS and 9.2 mol O2.
Once the reaction has occurred as completely as possible, what amount (in moles) of the excess reactant remains?
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You know the right answer?
Zinc sulfide reacts with oxygen according to the reaction:
2ZnS(s)+3O2(g)→2ZnO(s)+2SO2(g)
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