PLEASE HELP ASAP WITH THIS

Molar mass of Al = 26.98 g/mol

mass of Al = 33.0 g

we have below equation to be used:

number of mol of Al,

n = mass of Al/molar mass of Al

=(33.0 g)/(26.98 g/mol)

= 1.223 mol

Molar mass of Cl2 = 70.9 g/mol

mass of Cl2 = 38.0 g

we have below equation to be used:

number of mol of Cl2,

n = mass of Cl2/molar mass of Cl2

=(38.0 g)/(70.9 g/mol)

Part B

we have the Balanced chemical equation as:

2 Al + 3 Cl2 ---> 2 AlCl3

2 mol of Al reacts with 3 mol of Cl2

for 1.2231 mol of Al, 1.8347 mol of Cl2 is required

But we have 0.536 mol of Cl2

so, Cl2 is limiting reagent

we will use Cl2 in further calculation

Molar mass of AlCl3 = 1*MM(Al) + 3*MM(Cl)

= 1*26.98 + 3*35.45

= 133.33 g/mol

From balanced chemical reaction, we see that

when 3 mol of Cl2 reacts, 2 mol of AlCl3 is formed

mol of AlCl3 formed = (2/3)* moles of Cl2

= (2/3)*0.536

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.