Naturally occurring bromine is composed of two isotopes: 50.69 % Br-79 (mass of 78.9183 amu) and 49.31 % Br-81(mass of 80.9163 amu). Naturally occurring oxygen is composed of three isotopes: 99.757% O-16 (mass of 15.9949 amu), 0.038% O-17 (mass of 16.9991 amu), and 0.205% O-18 (mass of 17.9991 amu). The compound dibromonoxide is composed of two bromine atoms and one oxygen atom bonded together to form the Br2O molecule. Give the masses of the three most abundant Br2O molecules.

B. a graduated substance

It could possibly be beneficial if the experiment is successful.

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.