1 point
3. According to Table 3, how do the different types of 5-carbon molecules
differ wit...
Chemistry, 28.09.2021 20:30 soonerlady19
1 point
3. According to Table 3, how do the different types of 5-carbon molecules
differ with respect to their viscosity?
The alkane has a higher viscosity than the aldehyde and the aldehyde has a higher
viscosity than the alcohol.
The alkane has a higher viscosity than the alcohol and the alcohol has a higher
viscosity than the aldehyde
The alcohol has a higher viscosity than the alkane and the alkane has a higher
viscosity than the aldehyde.
The alcohol has a higher viscosity than the aldehyde and the aldehyde has a higher
viscosity than the alkane
Answers: 1
Chemistry, 22.06.2019 02:50, Jerrikasmith28
The conventional equilibrium constant expression (kc) for the system below is: 2icl(s) ⇄ i2(s) + cl2(g) [cl2] ([i2] + [cl2])/2[icl] [i2][cl2]/[icl]2 none of the listed answers are correct [i2][cl2]/2[icl]
Answers: 2
Chemistry, 22.06.2019 06:30, angelrenee2000
Ineed someone to see if my answers are correct! if any are wrong let me know what the correct answers would be and how to get that answer! 1. how many moles of sodium chloride are in 28 grams od nacl? a. 265 mole naclb. 856 mole naclc. 479 mole of nacld. 1.2 mole nacl < my choice2. 734 grams of lithium sulfate (li2so4) are dissolved to make 2500 ml of solution what is rhe molaratiy? a. 2.67 mb. 4.56 mc. 3.89 m < my choiced. 1.78 m3. how many grams of cacl2 would be dissolved in 3.0 l of a 0.50 m solution of cacl2? a. 250 g cacl2 b. 166.5 g cacl2c. 113.65 g cacl2d. 98 g cacl2 < my choice4. suppose you had 58.44 g of nacl and you dissolved it in exactly 2.00 liters. the molarity if the solution would be 0.5 mtrue < my choicefalse 5. i would need 22g of naoh to make a 3.0 m solution using 250 ml of solvent. true < my choicefalse6. identify the solute: you have a .0195 m solution made from using 6.5 g of solute and 3 l of solvent. identify the solute by solving for molar weight. a. the solute is nacl because the molar weight is 58.43 g/mol < my choiceb. the solute is h2so4 because the molar weight is 98.06 g/molc. the solute is cacl2 because the molar weight is 111.11 g/mol
Answers: 1
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