Chemistry, 25.09.2021 15:00 AnaiyaKirksey8

How many milliliters of 0.495 mol/L KOH solution are needed to completely neutralize 28.6 mL of 0.495 mol/L HI solution? The reaction is KOH(aq) + HI(aq) → KI(aq) + H2O(l)

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How many milliliters of 0.495 mol/L KOH solution are needed to completely neutralize 28.6 mL of 0.49...

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