What is the equilibrium concentration of NO if the equilibrium concentrations of N2 and O2 were measured to be 0.152 M and the value of the equilibrium constant, K, is 2.0 × 10-9? N2(g) + O2(g) ⇌ 2 NO(g)

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.

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just did the assignment and the answer was #1 +2 n