A major component of gasoline is octane (C, H, 8). When liquid octane is burned in air it reacts with oxygen (02) gas to produce carbon dioxide gas and water vapor. Calculate the moles of oxygen needed to produce 0.050 mol of water. Be sure your answer has a unit symbol, if necessary, and round it to the
correct number of significant digits.
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0.054 moles of carbon dioxide will be produced

Explanation:

Step 1: Data given

Number of moles oxygen = 0.085 moles

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate moles of carbon dioxide

For 2 moles octane we need 25 moles oxygen gas to produce 16 moles carbon dioxide gas and 18 moles water vapor

0.0544

For 0.085 moles O2 we'll have 16/25 * 0.085 = 0.054 moles CO2

0.054 moles of carbon dioxide will be produced

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.