Indicate whether or not each of the structures is considered to be aromatic. Both compounds are six atom rings arbitrarily numbered starting from the top and moving clockwise. Both have a carbon in position 1 that is bonded to an N H 2 where the nitrogen has a lone pair. Carbon 1 is double bonded to nitrogen in position two. This nitrogen has a lone pair. Position 3 is a carbon that is double bonded to an oxygen and the oxygen has two lone pairs. Position 5 and 6 is an alkene. Both compounds have a nitrogen in position 4, but the nitrogen in compound A is bonded to one methyl and has a lone pair on the nitrogen, whereas the nitrogen in compound B is bonded to two methyls and has a positive charge. Which is true

answer: - first one is the correct answer. .

explanations: - potassium sulfide is and cobalt(ii) chloride is .

charge on k is +1, charge on s is -2, charge on co is +2 and charge on cl is -1.

in a double replacement reaction the ion exchange takes place. in general the reaction looks like:

if one of the product is insoluble as per solubility rules then a precipitate of it is formed.

when we mix the aqueous solutions of potassium sulfide and cobalt(ii) chloride then chloride ion goes with potassium ion and sulfide ion goes with cobalt ion and the balanced equation is written as:

k and cl has equal charges, similarly co and s has equal charges and hence no subscripts are used for the product side.

as per the solubility rules, cos is insoluble and so it's precipitate is formed.

looking at the given choices, first choice is correct.