Consider the following equilibrium: A2 (g) + B2 (g) ⇋ 2 AB (g)
If the value of Kc for this reaction is 116.4, and the initial concentrations of each species are: [A2] = 0.200 M, [B2] = 0.200 M, [AB] = 0.140, what will be the equilibrium concentration of AB (in M)?

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

→

it's all four options.

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72

the ratio of the conjugate base to the acid required to attain the desired ph.