trộn V₁ lit dung dịch BA(OH)₂ có pH=12 với V₂ lit dd HNO₃ pH=2 thu được ( V₁+ V2) lit dd có pH=10. Tỉ lệ V₁: V₂=?

i think that the answer is c

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol