Express the frequency in inverse seconds. n=5-->n=1

Calculate the frequency of the light emitted when an electron in a hydrogen atom makes each of the following transitions.

n=4 -> n=3

n=5 -> n=1

n=5 -> n=4

n=6 -> n=5

when i did the first one i got 1.60*10^14, which was right, but when i did the second one the same way i got it wrong. could sombody show me how to do it so i can know what im doing wrong?

each time you need to use the same formula: delta E = Efinal -Einitial

Efinal = E1 = -2.18 x 10-18 J / 1^2

Einitl= E5 =  -2.18 x 10-18 J / 1^5

then use E = hv

u should get correct answer unless u r not making any calculation mistake

Explanation:

може ли да зареждате повече информация, моля