Calculate the number of atoms present in 1.4g of N² molecule​

 6.02x10^22 atoms

Explanation:  1.4 grams is (1.4g/28 g/mole) = 0.05 moles of N2.

(0.05 moles)*(6.02x10^23 molecules/mole) = 3.01x10^22 molecules

(3.01x10^22 molecules)(2 atoms/molecule) = 6.02x10^22 atoms

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2