Chemistry, 24.08.2021 01:20 1044537

Consider these equations: 2S (s) + 3O2 (g)→2SO3 (g), ΔH = −792
kJ 2S (s) + 2O2 (g)→2SO2 (g), ΔH =?
2SO2 (g) + O2 (g)→2SO3 (g), ΔH = −198 kJ
What is the missing ΔH?
−594 kJ
−198 kJ
+198 kJ
+792 kJ

Answers: 2

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Consider these equations: 2S (s) + 3O2 (g)→2SO3 (g), ΔH = −792
kJ 2S (s) + 2O2 (g)→2SO2 (g),...

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Consider these equations: 2S (s) + 3O2 (g)→2SO3 (g), ΔH = −792 kJ 2S (s) + 2O2 (g)→2SO2 (g), ΔH =? 2SO2 (g) + O2 (g)→2SO3 (g), ΔH = −198 kJ What is the missing ΔH? −594 kJ −198 kJ +198 kJ +792 kJ

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Other questions on the subject: Chemistry

Questions in other subjects:

Consider these equations: 2S (s) + 3O2 (g)→2SO3 (g), ΔH = −792
kJ 2S (s) + 2O2 (g)→2SO2 (g), ΔH =?
2SO2 (g) + O2 (g)→2SO3 (g), ΔH = −198 kJ
What is the missing ΔH?
−594 kJ
−198 kJ
+198 kJ
+792 kJ