An excess of a divalent metal M was dissolved in a limited volume of hydrocloric acid. If 576cm³ of hydrogen was librated at s. t.p , what was the mass of metal that produced this volume of gydrogen?( M = 24, H = 1 , molar volume of gas at s. t.p = 22.4dm³)

14.8 g

Explanation:

step 1 You first have to convert the cm^3 to dm^3 by dividing the volume by 1000 then find the number of mols for Hydrogen gas

from there you can use the of moles for hydrogen to find the moles of the metal step 2

then step 3 you multiply the number of by The Mr or Fr giving you your mass

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.