Chemistry, 16.08.2021 14:00 khynia11

Uppose there was a release of 1 mole of Alpha emission particle and 1 mole of Beta emission particles and both particles are accelerated to 20.50 MeV. What is the total energy in kJ/nuclei? Hint: 1 MeV = 1 x 106 eV and 1 eV = 1.602 X 10-19 J and 1 kJ = 1000 J, and finally in 1 mole there are Avogadro's number of particles which is 6.02214 x 1023 particles/mole. Report your answer in scientific notation to 2 decimal places for example 1.23 x 10-4 would be entered as 1.23 E-4. 238 92 U → 4 2 He + 234 90 Th and then 234 90 Th → 0
-1e + 234 91 Pa

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Uppose there was a release of 1 mole of Alpha emission particle and 1 mole of Beta emission particle...