The volume of real gas will change if “P” increases upto 500 atm and temperature decrease upto 0°C A. Volume increases by 0.05% B. Volume decreases by 0.05% C. Volume increases 20% D. Vol decreases 20%

We have that The volume of real gas will change if “P” increases upto 500 atm and temperature decrease upto 0°C there will be

. Volume decreases by 0.05%

OPtion B

From the question we are told that

if “P” increases upto 500 atm

temperature decrease upto 0°C

Generally the equation for the ideal gas equation  is mathematically given as

P=\frac{nRT}{V}

Where

n=1

R=0.08

Therefore

The volume is directly proportional to temperature

Therefore

. Volume decreases by 0.05%

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first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

it's c. elements are placed in rows based on how may valencies electrons have.