The metal sample suspected of being aluminum is warmed and then submerged into water, which is near room temperature. The final temperature of the water and the metal is given below. The specific heat capacity of water is 4.18 J/g. oC. Calculate the specific heat capacity of the metal based on the data below. Remember heat lost = heat gained.
Type of metal used:
Trial 1 Trial 2 Trial 3
Mass of metal, g 2.746 g 2.750 g 2.900 g
Mass of water, g 15.200 g 15.206 g 15.201 g
Initial Temp. of Water, oC 24.7 oC 24.6 oC 24.5 oC
Initial Temp. of Metal, oC 72.1 oC 72.2 oC 71.9 oC
Final Temp of Water & Metal, oC 26.3 oC 26.2 oC 24.7 oC
ΔT for water, oC
ΔT for metal, oC
Specific heat capacity of metal, J/g. oC
Average specific heat capacity, J/g .oC (use two significant figures due to ΔT of water)
Answers: 2
Chemistry, 22.06.2019 18:30, chinadoll24
Asample of hydrated tin (ii) chloride (sncl2) has a mass of 4.90 g. when it is dehydrated, it has a mass of 4.10 g. which is the correct chemical formula for the hydrate? sncl2•2h2o sncl2•4h2o sncl2•6h2o
Answers: 2
Chemistry, 22.06.2019 22:30, brianna5626
How do limiting factors most affect population size? ostop population growthrestrict population growthincrease population sizeresult in positive impactso
Answers: 1
The metal sample suspected of being aluminum is warmed and then submerged into water, which is near...
Biology, 22.10.2019 20:00
English, 22.10.2019 20:00
Mathematics, 22.10.2019 20:00
Mathematics, 22.10.2019 20:00
Mathematics, 22.10.2019 20:00
History, 22.10.2019 20:00