Chemistry, 16.07.2021 02:20 Kennethabrown09
In some areas, drinking water is fluoridated to reduce tooth decay. The maximum acceptable concentration (MAC) of fluoride ions in drinking water is 1.50 ppm.
In Dublin, California, a malfunction occurred in the fluoridation equipment caused fluoride levels to rise as high as 200 ppm. This resulted in many people becoming ill.
During the malfunction, 618 kg of fluoride ions where injected into a storage tank of water. Given that the resulting concentration was 200 ppm, calculate the volume, in ML, of the water storage tank.
(Do not show your work in the space provided; record only your final answer with the correct number of significant digits and the proper units.)
Answers: 1
Chemistry, 22.06.2019 12:30, murtaghliam1
Word equation for k(s) +h2o(l) yield koh (aq) + h2
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Chemistry, 22.06.2019 14:50, rebeccamckellpidge
The table compares the number of electrons in two unknown neutral atoms. comparison of electrons atom number of electrons a 9 d 11 use this information to determine the number of valence electrons in the atoms. which of the following correctly compares the stability of tthe table compares the number of electrons in two unknown neutral atoms. comparison of electrons atom number of electrons a 9 d 11 use this information to determine the number of valence electrons in the atoms. which of the following correctly compares the stability of the two atoms? both are unreactive. both are highly reactive. a is unreactive and d is reactive. a is reactive and d is unreactive.
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Chemistry, 22.06.2019 21:50, BookandScienceNerd
Answer the questions about this reaction: nai(aq) + cl2(g) → nacl(aq) + i2(g) write the oxidation and reduction half-reactions: oxidation half-reaction: reduction half-reaction: based on the table of relative strengths of oxidizing and reducing agents (b-18), would these reactants form these products? write the balanced equation: answer options: a. 0/na -> +1/na+1e- b. nai(aq) + cl2(g) → nacl(aq) + i2(g) c. +1/na+1e- -> 0 /na d. -1/2i -> 0/i2+2e- e. no f. 4nai(aq) + cl2(g) → 4nacl(aq) + i2(g) g. 2nai(aq) + cl2(g) → 2nacl(aq) + i2(g) h. 4nai(aq) + 2cl2(g) → 4nacl(aq) + 2i2(g) i. nai(aq) + cl2(g) → nacl(aq) + i2(g) j. 0/cl2+2e -> -1/2cl- k. yes
Answers: 1
In some areas, drinking water is fluoridated to reduce tooth decay. The maximum acceptable concentra...
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