g In the elimination reaction of t-butanol and t-butyl bromide. A. They have a common intermediate and require a strong base B. Both reactions share a common intermediate and involve a similar leaving group C. One reaction goes through an E1 mechanism and the other an E2 mechanism D. Both reactions share a common intermediate and differ only in the leaving group

Both reactions share a common intermediate and differ only in the leaving group

Explanation:

The elimination reaction of tertiary alkyl halides usually occur by E1 mechanism. In E1 mechanism, the substrate undergoes ionization leading to the loss of a leaving group and formation of a carbocation.

Loss of a proton from the carbocation completes the reaction mechanism yielding the desired alkene.

In the cases of t-butanol and t-butyl bromide, the mechanism is the same. The both reactions proceed by E1 mechanism. The leaving groups in each case are water and chloride ion respectively.

if you mean hydrogen and oxygen then water is the product