1 mole of alkene CxH2x was fully burnt in oxygen. The products were analysed. 264g of Co2 and 108g of of H20 were produced. Use the information to balance the equation and work out the identity of CxH2x. CxH2x+ O2--> CO2+H2O
PLEASE CAN SOMEONE EXPLAIN THIS TO ME

C6H12

Explanation:

Step 1: Find the molar mass of carbon dioxide and water

MH2O = 2(1.008) + 16.00 = 1.802x10^1 g/mol

MCO2 = 12.01 + 2(16.00) = 4.401x10^1 g/mol

Step 2: Calculate the moles of the products

nH2O = 108g / 1.802x10^1 g/mol = 5.99 or about 6

nCO2 = 264g/ 4.401x10^1 g/mol = 5.99 or about 6

Step 3: Enter moles of carbon dioxide and water into the balanced equation

CxH2x + O2 = 6CO2 + 6H2O

Step 4: Balance

We see how there is six carbon dioxide on the right side which means there are six carbons in the equation.

This means x is equal to 6 in our equation.

If you plug the information into the equation you get:

C6H12 + O2 = 6 CO2 + 6 H2O

Now all that's left is to balance the oxygens

We see how there is 18 oxygens on the right side of the equation which means there must be 18 on the left side.

Because we have oxygen gas we divide 18 by 2 which means there are 9 O2's on the left side

Therefore, the balanced equation is C6H12 + 9O2 = 6 CO2 + 6 H2O