How many grams of hydrogen is produced from 12.5 G of MG reacting with hydrochloric acid in this balanced equation? Mg+ 2HCL —>MgCl2+H2

1.03 grams of hydrogen is produced from 12.5 g of Mg reacting with hydrochloric acid.

Explanation:

The balanced reaction is:

Mg+ 2 HCl → MgCl₂ + H₂

By stoichiometry of the reaction, the following amounts of moles of each compound participate in the reaction:

Mg: 1 moleHCl: 2 molesMgCl₂: 1 moleH₂: 1 mole

Being the molar mass of each compound:

Mg: 24.31 g/moleHCl: 36.45 g/moleMgCl₂: 95.21 g/moleH₂: 2 g/mole

By reaction stoichiometry, the following mass amounts of each compound participate in the reaction:

Mg: 1 mole* 24.31 g/mole= 24.31 gHCl: 2 moles* 36.45 g/mole= 72.9 gMgCl₂: 1 mole* 95.21 g/mole= 95.21 gH₂: 1 mole* 2 g/mole= 2 g

Then you can apply the following rule of three: if by stoichiometry 24.31 grams of Mg produces 2 grams of H₂, 12.5 grams of Mg produces how much mass of H₂?

mass of H₂= 1.03 grams

1.03 grams of hydrogen is produced from 12.5 g of Mg reacting with hydrochloric acid.

The answer is 3,5g co

Exothermic,  physical change after it is already baked