Calculate the molarity of 198 g of barium iodide (Bal2) in 2.0 l of solution

The molarity of 198 g of barium iodide in 2.0 L of solution is 0.253 M.

Explanation:

Given: Mass = 198 g

Volume = 2.0 L

Molarity is the number of moles of solute present in liter of a solution.

Moles is the mass of a substance divided by its molar mass. So, moles of barium iodide (molar mass = 391.136 g/mol) is calculated as follows.

Now, molarity is calculated as follows.

Thus, we can conclude that the molarity of 198 g of barium iodide in 2.0 L of solution is 0.253 M.

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