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Formula of xenon trioxide = XeO3

Relative atomic mass: Xe = 131.29, O = 16

Question 1

number of moles = mass / molar mass

n of XeO3 = 9.07 / 131.29 + 3(16)

= 0.05059 mol

number of moles = number of particle / Alvagadro's constant

0.05059 = number of molecule / 6.02 x 10²³

number of molecules = 3.046 x 10²²

Question 2

number of moles = number of particle / Alvagadro's constant

number of moles = 3.22 x 10²² / 6.02 x 10²³

number of moles = 0.05349 mol

number of moles = mass / molar mass

0.05349 = mass / 131.29 + 3(16)

mass = 9.590g