in heating a kettle of water on an electric stove, 3.34×10^3 J of thermal energy was provided by the element of the stove. yet, the water in the kettle gained only 5.95×10^2 J of thermal energy. determine the percent efficiency of the electrical element in heating the kettle of water
Answers: 3
= 3.34 × 10³ J
= 5.95 × 10² J
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in heating a kettle of water on an electric stove, 3.34×10^3 J of thermal energy was provided by the...
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