How many atoms of phosphorus are in 7.00 mol of copper(II) phosphate?

The number of phosphorus atoms in given amount of copper(II) phosphate is

Explanation:

We are given:

Moles of copper(II) phosphate = 7.00 mol

1 mole of copper(II) phosphate contains 3 moles of copper, 2 moles of phosphorus and 8 moles of oxygen atoms

Moles of phosphorus in copper(II) phosphate =

According to the mole concept:

1 mole of a compound contains number of particles

So, 7.00 moles of copper(II) phosphate will contain = number of phosphorus atoms.

Hence, the number of phosphorus atoms in given amount of copper(II) phosphate is

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.

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