2 – Consulte a tabela de potencial de redução e faça o que se pede para uma pilha formada entre o cobre (Cu) e o Magnésio (Mg). tabela de potencial de redução E° Mg2+(aq) + 2e- → Mg(s) E° = -2,37 V Ni2+(aq) + 2e- → Ni(s) E° = -0,25 V Fe3+(aq) + e - → Fe2+(s) E° = 0,77 V Cu2+(aq) + 2e- → Cu(s) E° = 0,34V87 a) Determine quem é o anodo e quem é o catodo. b) Escreva as semirreações de oxidação e redução. c) Escreva a equação global da pilha. d) A Notação da pilha. e) Determine a d. d.p

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.

i would say b

explanation:

but i think i would need more information than that

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8