A toy car that is 0.12 m long is used to model the actions of an actual size car that is 6 m long which ratio shows the relationship between the sizes of the model and the actual car ?

The correct answer is - 1:50.

Explanation:

Given:

Model toy car = 0.12 m

Actual size of car = 6 m

The ratio of model and actual car size = ?

Solution:

We know that 1 m = 100 cm

then, Model toy car - 0.12*100 = 12 cm

and size of the actual car - 6*100 - 600 cm

Then the ratio of  model and actual car size = model car size/ actual car size

= 12/600

= 1/50

Thus, the correct answer is - 1:50.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be