Reduction of 9-fluorenone: objective of this lab was to reduce 9-fluorenone (a ketone), to 9-fluorenol (an alcohol) using sodium borohydride as the reducing agent. Experimental data: 9-fluorenone: MW 180.20 g/mol mass used 0.6 grams methanol: MW 32.04 g/mol volume used: 6ml density: 0.792 NaBH4: MW 37.83 g/mol mass used 0.05 grams 9-fluorenol: MW 182.22 g/mol Balanced equation for the reaction is: 4C13H8O NaBH4 4CH3OH --> 4C13H10O NaB(OCH3)4 Calculate the potential yield (in grams) of 9-fluorenol for 9-fluorenone, methanol and NaBH4. From these potential yields identify the limiting reagent and theoretical yield.

the atomic mass is the bottom number on the element.

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explanation:

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally