A sample of oxygen gas has volume 150.0 mL, at 0.947 atm, what will be the volume of the gas at 750.12 mm of Hg if temperature remain constant.

143.9 mL

Explanation:

Applying,

PV = P'V' Equation 1

Where P = Initial pressure, V = Initial Volume, P' = Final pressure, V' = Final volume.

Make V' The subject of equation 1

V' = PV/P' Equation 2

From the question,

Given: P = 0.947 atm, V = 150 mL, P' = 750.12 mm of Hg = (750.12/760) = 0.987 atm,

Substitute these values  into equation 2

V' = (0.947×150)/0.987

V' = 143.9 mL