Urgent: Suppose that 14.9 mL of HNO3 is neutralized by 53.1 mL of a 0.0048 M solution of KOH in a titration. Calculate the concentration of the HNO3 solution.

0.017 M

Explanation:

The reaction that takes place is:

First we calculate how many KOH moles reacted, using the given volume and concentration:

As 1 mmol of KOH reacts completely with 1 mmol of HNO₃, in 14.9 mL of the HNO₃ solution there were 0.255 HNO₃ mmoles.

With that in mind we can calculate the concentration of the HNO₃ solution using the calculated number of moles and given volume:

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

the answer is a and have a great day