From a sample containing manganese sulfate, 1000 grams are taken and made up to 50 ml volume. Next, 25 ml of this solution is taken. Mn^+2 is titrated with 0.1M KMnO4. Consumption is 13ml. Another 1,000 gram portion taken is dissolved in some distilled water and precipitated with excess Ba2+ at pH:1. After the precipitate obtained is filtered and washed, the precipitate is boiled with 50mL of 0.125 M Na2EDTA solution and Ba2+ ions are taken into the solution as Ba(EDTA)2- complex. How many mL of 0.087M MgSO4 solution should be used for excess Na2EDTA?

Answer asap need it by wednesday morning carry out the following calculations on ph and ka of from data. i. calculate the ph of 0.02m hcl ii. calculate the ph of 0.036m naoh iii. calculate the ph of 0.36m ca(oh)2 iv. calculate the ph of 0.16m ch3cooh which has ka = 1.74 x 10-5 mol dm-3 v. calculate ka for weak acid ha which has a ph of 3.65 at 0.30m concentration vi. calculate the ka of a solution made by mixing 15.0 cm3 0.2m ha and 60.0 cm3 0.31m a-. [ph= 3.80] vii. calculate the ph of a solution made by mixing 15.0 cm3 0.1m naoh and 35.0 cm3 0.2m hcooh. [ka = 1.82 x 10-4 m]