Chemistry, 22.06.2021 02:40 Cate9216

Methanol (CH40) is converted to bromomethane (CH3Br) as follows: CH4O+HBr=CH3Br+H2O If 12.23 g of bromomethane are produced when 5.00 g of methanol is reacted with excess HBr, what is the percentage yield

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Methanol (CH40) is converted to bromomethane (CH3Br) as follows: CH4O+HBr=CH3Br+H2O If 12.23 g of br...