A 100.0-g sample of water at 27.0oC is poured into a 71.0-g sample of water at 89.0oC. What will be the final temperature of the water? (Specific heat capacity of water = 4.184 J/goC.)

The final temperature will be

Explanation:

Calculating the heat released or absorbed for the process:

In a system, the total amount of heat released is equal to the total amount of heat absorbed.

OR

......(1)

where,

C = heat capacity of water =

= mass of water of sample 1 = 100.0 g

= mass of water of sample 2 = 71.0 g

= final temperature of the system = ?

= initial temperature of water of sample 1 =

= initial temperature of the water of sample 2 =

Putting values in equation 1, we get:

Hence, the final temperature will be

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.