Question List (4 items) (Drag and drop into the appropriate area) Find the volume of HCl that will neutralize the base. Find the mass (in grams) of Ca(OH)2. Calculate the number of moles of Ca(OH)2. Calculate the number of moles of H required to neutralize the base.

The question is incomplete, the complete question is:

The solubility of slaked lime, , in water is 0.185 g/100 ml. You will need to calculate the volume of M HCl needed to neutralize 14.5 mL of a saturated

The volume of HCl required is 290mL, the mass of is 0.0268g, the moles of

Explanation:

Given values:

Solubility of = 0.185 g/100 mL

Volume of = 14.5 mL

Using unitary method:

In 100 mL, the mass of present is 0.185 g

So, in 14.5mL. the mass of present will be =

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

......(1)

Given mass of = 0.0268 g

Molar mass of = 74 g/mol

Plugging values in equation 1:

Moles of present =

The chemical equation for the neutralization of calcium hydroxide and HCl follows:

By the stoichiometry of the reaction:

Moles of = Moles of = 0.000724 mol

The formula used to calculate molarity:

.....(2)

Moles of HCl = 0.000724 mol

Molarity of HCl =

Putting values in equation 2, we get:

Hence, the volume of HCl required is 290mL, the mass of is 0.0268g, the moles of

c. 75.7

i think that is the right

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).