Find the boiling point of a solution of 2.00 m solution of sodium chloride, NaCl, in water (kb= 0.512°C, bp= 100.0°C)

Boiling point of the given solution is .

Explanation:

Given: Molality = 2.00 m

Now, equation for dissociation of water is as follows.

As it is giving 2 ions upon dissociation. So, the value of i = 2.

Formula used to calculate change in temperature is as follows.

where,

i = Van't Hoff factor

= molal boiling point elevation constant

m = molality

Substitute the values into above formula as follows.

As the boiling point of water is . Hence, the boiling point of solution will be as follows.

Thus, we can conclude that boiling point of the given solution is .

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