The number of molecules in 48.0 grams of oxygen gas o2 is

The correct answer is b.hoped i you

Answerit is not a suspension or colloid mixture, it is a solution mixture;

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Answer is:   -2,840 kj/mol.reaction of combustion of glucose: c₆h₁₂o₆ + 6o₂  → 6co₂ + 6h₂o.in reaction there is only one mole of glucose.heat of combustion is then δh = q/n = -2840 kj/1mol = -2,840 kj/mol.n - amount of substance.δh-    heat of combustion per mole.