How much heat is required to raise the temperature of 16.0 grams H2O from 5.000C to 75.00C? Below is a list of constants. specific heat for H2O(s) = 2.1 J/g0C

specific heat for H2O(L) = 4.18 J/g0C

specific heat for H2O(g) = 1.7 J/g0C

\bigtriangleup H△Hvap = 40.7 kJ/mol

\bigtriangleup H△Hfus = 6.01 kJ/mol

5.34 J

260 J

4680 J

2350 J

The amount of heat required is 4681.6 J.

Explanation:

mass, m = 16 g = 0.016 kg

initial temperature, T = 5 C

final temperature, T' = 75 C

specific heat, c = 4.18 J/g C

The amount of heat required is

H = m c (T'- T)

H = 16 x 4.18 x (75 - 5)

H = 4681.6 J

i know insulin is primary but i dont know the others im sorry

explanation:

where's the diagram?