Chemistry, 10.06.2021 03:20 mathwhiz9125

Information- The chemical equation is Mg(s) + O2(g) → MgO(s)

for trial 1,
the mass of empty crucible with lid is- 26.680 g
the mass of Mg metal, crucible and lid is- 26.993 g
the mass of MgO, crucible and lid is- 27.194 g

for trial 2,
the mass of empty crucible with lid is- 26.682 g
the mass of Mg metal, crucible and lid is- 27.100 g
the mass of MgO, crucible and lid is- 27.194 g

Questions-

1. Magnesium is the limiting reactant in this experiment. What is the theoretical yield of MgO for each trial?

2. what is the percent yield of MgO for the experiment for each trial?

3. what is the average percent yield of MgO for the two trials?

Answers: 1

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Information- The chemical equation is Mg(s) + O2(g) → MgO(s)

for trial 1,
the mas...