Xcc of 5N HCL was diluted to 1 litre of normal solution calculate the value of x​

200cc of 5N HCl were diluted

Explanation:n

Assuming the solution was diluted to prepare a 1N HCl solution:

The HCl was diluted from 5N to 1N, that is a dilution of:

5N / 1N = 5 times

As the total volume of the diluted solution is 1L = 1000mL = 1000cc the amount of the concentrated solution was:

1000cc / 5 =

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation:

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.