Determine the molar mass of a 0.458-gram sample of gas having a volume of 1.20 L at 287 K and 0.980 atm. Group of answer choices 1.954 g/mol 73.6 g/mol 7.18 g/mol 9.17 g/mol

Molar mass of gas = 9.17 g/mol

Explanation:

We'll begin by calculating the number of mole of the gas. This can be obtained as follow:

Volume (V) = 1.20 L

Temperature (T) = 287 K

Pressure (P) = 0.980 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

PV = nRT

0.980 × 1.2 = n × 0.0821 × 287

1.176 = n × 23.5627

Divide both side by 23.5627

n = 1.176 / 23.5627

n = 0.0499 mole

Finally, we shall determine the molar mass of the gas. This can be obtained as follow:

Mass of gas = 0.458 g

Number of mole = 0.0499 mole

Molar mass of gas =?

Mole = mass / molar mass

0.0499 = 0.458 / molar mass of gas

Cross multiply

0.0499 × molar mass of gas = 0.458

Divide both side by 0.0499

Molar mass of gas = 0.458 / 0.0499

Molar mass of gas = 9.17 g/mol

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the answer is a! (2.9 x 10^-18 j) hope i could someone. : )