What is the molarity if 60.4 grams of hydrochloric acid was added to 505 mL of water? M
H - 1.0079 g/mol
Cl- 35.453 g/mol

3.29 M

Explanation:

Molarity refers to the molar concentration of a solution and it can be calculated using the formula below:

Molarity (M) = number of moles (n) ÷ volume (V)

According to this question, the mass of HCl was given to be 60.4 grams and the volume of water as 505 mL.

Using mole = mass/molar mass to convert mass of HCl to moles

Molar mass of HCl = 1.0079 + 35.453 = 36.4609g/mol

mole = 60.4g ÷ 36.4609g/mol

mole = 1.66mol

Volume of water = 505mL = 505/1000 = 0.505L

Molarity, M = 1.66 ÷ 0.505

Molarity of HCl solution = 3.29 M

indium, and thallium have three electrons i think

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.