Using a separate sheet of paper, explain using the solution notes how you would prepare a 100 mL solution of 1 M of glucose(C6H1206).

C6irc68rd6rid5rucr5u i6i iyf yif ify iyf ify yfi itf yfi yfi icy yfi yci yci iyc iyf iyf

The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.

Iam pretty sure that the answer is d

Answer-ide.