What is the mole fraction of ethanol when 23.2 g of ethanol(C2H5OH) are mixed with 73.1 g of water(H2O)? (atomic mass of C= 12, H = 1, O = 16,)

0.111

Explanation:

Step 1: Calculate the moles corresponding to 23.2 g of ethanol

The molar mass of C₂H₅OH is 46 g/mol.

23.2 g × 1 mol/46 g = 0.504 mol

Step 2: Calculate the moles corresponding to 73.1 g of water

The molar mass of H₂O is 18 g/mol.

73.1 g × 1 mol/18 g = 4.06 mol

Step 3: Calculate the total number of moles

n = nC₂H₅OH + nH₂O = 0.504 mol + 4.06 mol = 4.56 mol

Step 4: Calculate the mole fraction of ethanol

We will use the following expression.

Χ(C₂H₅OH) = nC₂H₅OH / n

Χ(C₂H₅OH) = 0.504 mol / 4.56 mol = 0.111

the answer would be b i believe