Suppose a current of 0.860A flows through a copper wire for 5.0 minutes. Calculate how many moles of electrons travel through the wire. Be sure your answer has the correct unit symbol and round your answer to 2 significant digits.

2.7×10⁻³ mole

Explanation:

Applying

Q = it Equation 1

Where Q = amount of charge, i = current, t = time

From the question,

Given: i = 0.860 A, t = 5 minutes = (5×60) seconds = 300 seconds

Subsitute these values into equation 1

Q = (0.860×300)

Q = 258 C

If one mole of electron has a charge of 96500 C

Then, x mole of electron will have a charge of 258 C

1 mole ⇒ 96500 C

X moles ⇒ 258 C

Solve for X

X = (258×1)/96500

X = 2.7×10⁻³ mole

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

it would be d. henry moseley

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