A. how many grams of H2SO4 are in 3.5 liters of 2.0 M H2SO4 b. how many liters of 2.0 M H2SO4 would be made from 3 liters of water. (Hint water has a density of 1g per mL.)

a. 686g of H2SO4 are present.

b. 3.321L would be made

Explanation:

a. Molarity, M, is an unit of concentration defined as the ratio between moles of solute (In this case H2SO4) and liters of solution. The moles of H2SO4 in 3.5L of 2.0M H2SO4 are:

3.5L * (2.0mol H2SO4 / L) = 7.0 moles H2SO4

The mass is obtained using molar mass of H2SO4 -98g/mol-:

7.0 moles H2SO4 * (98g / mol) = 686g of H2SO4 are present

b. The density of H2SO4 is 1.83g/mL. The volume of 2.0M H2SO4 per liter of solution is:

2.0mol H2SO4 / L * (98g / mol) * (1mL / 1.83g) = 107mL of H2SO4 are present per liter of solution. In 3L there are:

3L  (107mL / L) = 321mL = 0.321L of H2SO4 must be added to 3L of water to produce 2.0M H2SO4. The total volume is:

3L + 0.321L = 3.321L would be made

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: